the root of the equation z/4= -8is
Answers
First of all root means the zero of the solution or the value by which when variable is replaced then the L.H.S=R.H.S
So here,
L.H.S=Z/4
R.H.S=-8
since we need to find root
L.H.S=R.H.S
Z/4=-8
Z=-32
Simple mathematics but very important would suggest to go through the rd sharma book of your respective class to strengthen your concept
Answer:
hope it will help you
Step-by-step explanation:
ANSWER
z
1
=(z
3
−z
2
)×e
i
3
π
+z
2
⇒z
1
=
2
1
×(z
3
−z
2
)(1+i
3
)+z
2
⇒2z
1
=(z
3
−z
2
)(1+i
3
)+2z
2
⇒2z
1
=z
3
(1+i
3
)+z
2
(1−i
3
)
⇒z
2
=
1−i
3
1
×[2z
1
−z
3
(1+i
3
)]
⇒2z
2
=
2
1
(2+i2
3
)z
1
−
2
1
(1+i
3
)
2
z
3
⇒2z
2
=(1+i
3
)z
1
+(1−i
3
)z
3
Now, 2(z
2
+z
4
)=2(z
1
+z
3
) since the diagonals bisect each other.
∴2z
4
=2z
1
+2z
3
−2z
2
∴2z
4
=2z
1
+2z
3
−(1+i
3
)z
1
−(1−i
3
)z
3
i.e. 2z
4
=(1−i
3
)z
1
+(1+i
3
)z
3