the root of the quadratic equation 3xsq_2root6x+2=0
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3x^{2}x2 -2√6x+2=0
3x^{2}x2 -√6x-√6x+2=0
√3x^{2}x2 *√3x^{2}x2 -√3x*√2x-√3x*√2x+√2*√2=0
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2)(√3x-√2)=0
x=√2/√3
Therefore the equation has two equal roots; √2/√3
bye frnd
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