Question

the root of the quadratic equation 3xsq_2root6x+2=0

Answer 1

Answer:

3x^{2}x2 -2√6x+2=0

3x^{2}x2 -√6x-√6x+2=0

√3x^{2}x2 *√3x^{2}x2 -√3x*√2x-√3x*√2x+√2*√2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-√2)(√3x-√2)=0

x=√2/√3

Therefore the equation has two equal roots; √2/√3

bye frnd