Question

The root of the quadratic equation 6x²-x-2=0 are

Answer 1

Step-by-step explanation:

6x^2-x-2

=6x^2-4x+3x-2

=2x(3x-2)+1(3x-2)

=(2x+1)(3x-2)

x= -1/2 or 2/3

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Answer 2

Answer:

Step-by-step explanation:

6x^2-4x+3x-2=0

2x(3x-2)+1(3x-2)=0

(2x+1) (3x-2)=0

So either 3x-2=0 or 2x+1=0

X=2 /3 or -1/2