Question

The root of the quadratic equation are (1+root 2) and (1+root 2).from the quadratic equation.​

Answer 1

Looks like, your question has (1 + root2) and (1 - root2).

Answer:

x² - 2x - 1

Step-by-step explanation:

Sum of roots = (1 + √2) + (1 - √2)

                  S = 2

Product of roots = (1 + √2)(1 - √2)

                        P = 1 - (√2)²

                            = 1 - 2

                            = - 1

 Quadratic equation:

⇒ x^2 - Sx + P

⇒ x^2 - 2x + (-1)

⇒ x^2 - 2x - 1

Answer 2

Answer:

if one root of the quadratic equation is 1+√2 other root must be conjugate the second root is 1-√2

${x}^{2} - (1 + \sqrt{2} \: + 1 - \sqrt{2} \: )x + \\ (1 + \sqrt{2} \: )(1 - \sqrt{2} \: ) = 0 \\ {x}^{2} - 2x \: - 1 = 0$

hope it's helpful