The root of
the quadratic equation y2 - 2y - 63 =0 are
Answers
Answer:
y = 9 and -7
Step-by-step explanation:
==: y² - 2y - 63 = 0
==: y² - 9y + 7y - 63 = 0
==: y (y - 9) + 7 (y - 9) = 0
==: (y - 9) (y + 7) = 0
==: y = 9 and -7
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Answer:
hey mate.... ur answer is -7, 9
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 1 • -63 = -63
Step-2 : Find two factors of -63 whose sum equals the coefficient of the middle term, which is -2 .
-63 + 1 = -62
-21 + 3 = -18
-9 + 7 = -2 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 7
y2 - 9y + 7y - 63
Step-4 : Add up the first 2 terms, pulling out like factors :
y • (y-9)
Add up the last 2 terms, pulling out common factors :
7 • (y-9)
Step-5 : Add up the four terms of step 4 :
(y+7) • (y-9)
Which is the desired factorization
y + 7 = 0 / y + (-9) = 0
y = -7 , 9
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