Question

the root of the quadratic equations 6x2_x_0=​

Answer 1

Answer:

x=23

Step-by-step explanation:

equation is 6x2−x−2=06x2-x-2=0

let α&βα&β be two terms such that

α+β=−xα+β=-x

α⋅β=(6x2)(−2)=−12x2α⋅β=(6x2)(-2)=-12x2

α=−4x&β=3xα=-4x&β=3x

6x2−4x+3x−2=06x2-4x+3x-2=0

2x[3x−2]+1[3x−2]=02x[3x-2]+1[3x-2]=0

(2x+1)(3x−2)=0(2x+1)(3x-2)=0

2x+1=02x+1=0

x=−12x=-12 answer

and 3x−2=03x-2=0

x=23x=23 answer