Question

The root of x² -4x-12=0 are

Answer 1

Answer:

6, -2

Step-by-step explanation:

your answer

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Answer 2

Step-by-step explanation:

f (x ) = 0

x^(2)-4x -12 =0

x=

$- b + or - \ \sqrt{b {}^{2} } - 4ac \div 2a$

$a x^{2} + bx + c = 0$

a =1 b= -4 c= -12

i.e , -(- 4 ) +/-

$- ( - 4) + or - \sqrt{(( - 4) ^{2} } - 4 \times 1 \times - 12 )\div 2 \times 1)$

x=

$-4 + or - \sqrt{4 + 48 \div 2 }$

x=

$4 + or - \sqrt{36} = 4 + or - 6$

Values of x are x= 4+6 =10

x = 4-6 = -2