Question

the root of x2+x-6=0 are​

Answer 1

Solution :-

${x}^{2} + x - 6 = 0 \\ \\ {x}^{2} + 3x - 2x - 6 = 0 \\ \\ x(x + 3) - 2(x + 3) = 0 \\ \\ (x + 3)(x - 2) = 0 \\ \\ x = - 3 \: and \: 2$

Answer 2

Answer:

x^2+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

x=-3 or x=2