The root root of the square equation 2x² + 3x-5 = 0 is x1 and x2. If x1> x2, then the value of 4x1 + 3x2
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Answered by
2
2x ^ 2 + 3x-5 = 0
(2x + 5) (x-1) = 0
x = -5/2, x = 1
Then,
x1 = 1, x2 = -5/2
4x1 + 3x2 = 4-15 / 2
= -7/2
(2x + 5) (x-1) = 0
x = -5/2, x = 1
Then,
x1 = 1, x2 = -5/2
4x1 + 3x2 = 4-15 / 2
= -7/2
Answered by
1
hi friend,
2x²+3x-5=0
→2x²+5x-2x-5=0
→ x(2x+5)-1(2x+5)=0
→(x-1)(2x+5)=0
x1 is 1 and x2 is -5/2
now.,4x1 + 3x2→4(1)+3(-5/2)
→4-15/2
→-7/2
I hope this will help u :)
2x²+3x-5=0
→2x²+5x-2x-5=0
→ x(2x+5)-1(2x+5)=0
→(x-1)(2x+5)=0
x1 is 1 and x2 is -5/2
now.,4x1 + 3x2→4(1)+3(-5/2)
→4-15/2
→-7/2
I hope this will help u :)
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