Question

the root x²+2x-3=0 is​

Answer 1

Step-by-step explanation:

The roots of the above polynomial are -3 and 1

Answer 2

Step-by-step explanation:

$x²+2x-3=0$

Comparing the equation with ax² + bx + c = 0,

$a = 1 , \: \: b = 2 , \: \: c = -3$

$a \times c = 1 \times ( - 3) = - 3$

$x²+2x-3=0$

$x²+3x - x-3=0$

$x(x + 3) - 1(x + 3) = 0$

$(x + 3)(x - 1) = 0$

$x + 3 = 0\: \: or \: \: x - 1= 0$

$x = - 3 \: \: or \: \: x = 1$

$So, \: x = - 3,1$

I hope it is helpful