The roots a and ß of the quadratic equation x2-5x+3(k-1)=0 are such that a-
B=1. Find the value k.
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α + β = 5 --- (1)
α - β = 1 --- (2)
Solving (1) and (2), we get
α = 3 and β = 2
Also αβ = 6
Or 3(k - 1) = 6
k - 1 = 2
k = 3
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