The roots & and ß of the quadratic
u² – Ju +3 QK-1) = 0 are
such that a-b=1. find vele of
equation
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Answer:x2-5x+3(k-1)
Given:
alpha-beta=1
alpha=1+beta
alpha+beta=-b/a
1+beta+beta=-(-5)/1
1+2beta=5
2beta=5-1
2beta=4
beta=2
alpha=1+beta
alpha=1+2
alpha=3
alpha*beta=c/a
3*2=3(k-1)
6=3(k-1)
6/3=k-1
2=k-1
2+1=k
3=k
Step-by-step explanation:
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