The roots α and β of the quadratic equation x2
-5x+3(k-1)=0 are such that α-
β=1. Find the value k.
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Given:
The roots α and β of the quadratic equation - 5x + 3(k-1) = 0 are such that
α - β =1.
To Find:
Find the value k.
Solution:
We know that,
- 5x + 3(k-1)
α - β = 1
α = 1 + β
So,
α + β = -b/a
1 + β + β = -(-5)/1
1 + 2β = 5
2β = 5-1
2β = 4
β = 2
α = 1 + β
α = 1 + 2
α =3
α*β = c/a
3*2 = 3(k-1)
6 = 3(k-1)
6/3 = k - 1
2 = k - 1
2 + 1 = k
3 = k
Hence, k has a value of 3.
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