The roots α and β of the quadratic equation x² -5x + 3 (k-1) = 0 are such that α-β =1 .
Find the value of k.
Answers
Answer:
α + β = 5 --- (1)
α - β = 1 --- (2)
Solving (1) and (2), we get
α = 3 and β = 2
Also αβ = 6 Or 3(k - 1) = 6
k - 1 = 2
k = 3
→ Hey Mate,
→ Given Question:-
→ The roots α and β of the quadratic equation x² - 5x + 3 (k-1) = 0 are such that α - β = 1. Find the value of k.
→ To Find:-
→ Find the value of k?
→ Solution:-
→ x² -5x + 3( k - 1) = 0
→ α = 1
→ β = -5
→ c = 3 (k - 1)
→ α - β = 1
→ α - 1 = β
→ Sum of roots = α + β = -b / α
→ = α + α - 1 = - ( -5) / 1
→ = 2α - 1 = 5
→ = 2α = 6 (∵ 2 and 6 gets cancels)
→ so, = α = 3
→ β = α - 1
→ = 3 - 1
→ = 2
→ so , β = 2
→ Product of roots = αβ = c / a
→ = 3(2) = 3k - 3 / 1
→ = 6 = 3k - 3
→ = 6 + 3 = 3k
→ = 9 = 3k
→ = k = 3
→ ∴ The Value of k is 3.
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