Question

The roots of 14x² + x = 3 , are *

-1/2 and -3/7
-2 and -7/3
-7/2 and 3
-1/2 and 3/7

Answer 1

$14 {x}^{2} - x = 3 \\ 14 {x }^{2} - x - 3 = 0 \\ 14 {x}^{2} - 7x + 6x - 3 = 0 \\ 7x(2x - 1) + 3(2x - 1) = 0 \\ (2x - 1)(7x + 3) = 0$

Therefore, Zeroes of 14x² + x = 3 are

$\frac{1}{2} \: \: and \: \: \frac{ - 3}{7}$

hope it will help u ✨☺️

Answer 2

Step-by-step explanation:

Therefore,

-1/2 and 3/7 are the roots.