Question

The roots of 15x2 +14x-8= 0 are​

Answer 1

Answer:

roots are 2/5 and -4/3

Step-by-step explanation:

Given quadratic equation, $15x^{2} +14x-8=0$

Let's solve it by splitting middle term.

$15x^{2} +14x-8=0\\\\ 15x^{2} -6x+20x-8=0\\\\ 3x(5x-2)+4(5x-2)=0\\\\(5x-2)(3x+4)=0\\\\ (5x-2)=0 => x = \frac{2}{5} \\\\ (3x+4)=0=>x=\frac{-4}{3} \\\\\\\ The \ roots \ are \ \frac{2}{5} \ and \ \frac{-4}{3}$

Answer 2

Required Answer:-

• The roots of the equation are 2 / 5 and - 4 / 3

Given:

• Quadratic Equation : 15x² + 14x - 8 = 0

To Find:

• The roots of the Equation

Solution:

⇒ 15x² + 14x - 8 = 0

Splitting the middle term :

⇒ 15x² + 20x - 6x - 8 = 0

⇒ 5x ( 3x + 4 ) - 2 ( 2x + 4 )

⇒ ( 5x - 2 ) ( 3x + 4 ) = 0

Now the roots are :

→ 5x - 2 = 0

→ 5x = 2

→ x = 2 / 5

And,

→ 3x + 4 = 0

→ 3x = - 4

→ x = - 4 / 3

Hence:

• The roots of the equation are 2 / 5 and - 4 / 3

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