Question

The roots of 2x^2-6x+7=0 are
1)imaginary
2) real number and equal
3)not a real number
4)non of these ​

Answer 1

Answer:

imaginary

Step-by-step explanation:

(b²-4ac)

=(-6)²-4×2×7

=36-56

=-20<0

the roots of the equation are imaginary

Answer 2

Given:

• A quadratic equⁿ is given to us .
• The equⁿ is 2x²-6x+7=0.

To Find:

• The nature of the roots.

Answer:

Before we proceed have a look at this:

$\begin{tabular}{|c|c|} \cline{1-2} Condition & Nature of Roots \\ \cline{1-2} If D > 0 & Real Roots \\ \cline{1-2} If D=0&Equal roots \\ \cline{1-2}If D < 0 & Imaginary Roots(Complex Nos.)\\ \cline{1-2} \end{tabular}$

Here with respect to Standard form of a quadratic equⁿ , ax² + bx + c ,

• a = 2.
• b = (-6).
• c = 7 .

So , here Discriminant = b² - 4ac .

➥ D = (-6)² - 4 × 2 × 7 .

➥ D = 36 - 56.

➥ D = (-20) .

Here we can see that D < 0 , hence the roots are complex number , which means not a real number.

[ CORRECT OPTION - 3 ]