Question

The roots of 35x^{2} +13x- 12=0

Answer 1

Answer:

-(4\5). or. 3\7

Step-by-step explanation:

$35 {x}^{2} + 13x - 12 = 0 \\ 35 {x}^{2} + 28x - 15x - 12 = 0 \\ 7x(5x + 4) - 3(5x + 4) = 0 \\ (5x + 4)(7x - 3) = 0 \\ 5x + 4 = 0 \: \: \: or \: \: 7x - 3 = 0 \\ x = - \frac{4}{5} \: \: or \: \: \: \: x = \frac{3}{7}$

Answer 2

Correct Question :

Find the roots of the equation 35x²+13x-12=0.

Solution :

A quadratic equation is the equation that has the degree 2 and is in the form ax²+bx+c=0.

To find the roots of the equation we have two methods,

• Middle term factorization
• By using formula

So by using middle term factorization,

35x²+13x-12=0

35x²+28x-15x-12=0

35x²-15x+28x-12=0

5x(7x-3)+4(7x-3)=0

(5x+4)(7x-3)=0

$Therefore \:$

5x+4=0

5x= - 4

x = - 4 /5

Or

7x-3=0

7x=3

x = 3/7

$Therefore \: the \: roots \: of \: the \: equation \\\: are \: ( \frac{ - 4}{5} ) \: and \: ( \frac{3}{7} ).$

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