Math, asked by VenkataSatish, 9 months ago

The roots of √3x² + 10x - 8√3=0 are​

Answers

Answered by Rudra0936
11

Answer:

The Quadratic equation is

√3x²+10x-8√3 = 0✓

so to find the roots of this eq we need to apply the sridhar acchariyas formula to this equation which is as follows:-

x= -b±D / 2a

 \sqrt{3x ^{2} }  + 10x - 8 \sqrt{3}  = 0

Here a= √3 ,b= 10 c= -8√3

So , X=

 \frac{ - b \: plus \: minus \:  \sqrt{b ^{2}  - 4ac} }{2a}

 \frac{ - 10 \: plus \: \: minus \:  \sqrt{100 + 96} }{2 \sqrt{3} }

 \frac{ - 10 \: plus \: minus14}{2 \sqrt{ 3} }

ether

x =  \frac{ - 10 - 14}{2 \sqrt{3} } \: or \frac{  - 10 + 14}{2 \sqrt{3} }

x =  \frac{ - 24}{2 \sqrt{3} } \: or \:  \frac{4}{2 \sqrt{3} }

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