Question

The roots of 3x²+4x-7=0 are

Answer 1

Answer:

3x^2+4x-7=0

=> 3x^2+7x-3x-7=0

=> x(3x+7)-1(3x+7)=0

=> (3x+7)(x-1)=0

=> 3x+7=0

=> 3x= -7

=> x= -7/3

again, x-1=0

=> x=1

so, x=1 , -7/3

Answer 2

$\bold{x = \frac{ - b \underline{ + } \sqrt{ {b}^{2} - 4ac }}{2a} }$

$\bold{3x²+4x-7=0}$

a= 3

3b= 4

4c= -7

$\bold{x = \frac{ - 4 \underline{ + } \sqrt{ {4}^{2} - 4 \times 3( - 7) }}{2 \times 3} }$

$\bold{x = \frac{ - 4 \underline{ +} 10}{6} }$

$\bold{x = \frac{ - 4 { +} 10}{6} }$

$\bold{x = \frac{ - 4 { - } 10}{6} }$

$\bold{x = 1}$

$\bold{ { x = - \frac{7}{3} }}$