The roots of a x square + bx + c is equal to zero are real and positive
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Given
D=0
b2-4ac=o
x2+bx+c
b2-4.1.c=0
b2-4c=0
b2=4c
b=+root of 4c or -root of 4c
D=0
b2-4ac=o
x2+bx+c
b2-4.1.c=0
b2-4c=0
b2=4c
b=+root of 4c or -root of 4c
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