Question

the roots of alpha and beta of a quadratic equation x^2-5x+3(k-1)=0 are such that alpha minus beta =1 . Find the value of k​

Answer 1

Answer:

2x2 + 5x + k = 0

The quadratic equation is

x= (-b ±√(b2-4ac))/2a

If b2-4ac is less than zero the roots are not real.

a=2, b=5, c = k

b2-4ac<0

52-4(2)k <0

25-8k <0

-8k < -25

k>25/8

k>3.125

In interval notation: (3.125, ∞)