the roots of alpha and beta of a quadratic equation x^3-5x+2(k-1)=0 are such that alpha minus alpha beta =1.Find the value of k
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Answer:
Given x
2
−5x+3(k−1)=0 α,β are roots is given equation.
α−β=11 __________ (1)
using conditions we have α+β=5
αβ=3(k−1)
now α−β=
α
2
+β
2
−2αβ
=
(α+β)
2
−4αβ
(11)
2
=(α+β)
2
−4αβ
121−25=−12(k−1)⇒
12
96
=1−k
[k=-7]
Hence value of k is -7.
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