the roots of alpha and beta of the quadratic equation X square - 5 x + 3 into k - 1 equal to zero are such that alpha minus beta is equal to 1 find the value of k
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Step-by-step explanation:
x2-5x+3(k-1)=0
x2-5x+3k-3=0
alpha+beta=-b/a
=5/1=5 -----Eq-1
alpha-beta=1 (given) ------Eq-2
By solving Equations 1 and 2,
2alpha=6
alpha=3
So, put the value of alpha in Eq-1,
3+beta=5
beta=2
alpha × beta= c/a
3 × 2= 3k-3
6=3k-3
3k=6+3
3k=9
k=9/3
k=3 -: Answer
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