Question

The roots of ax² + bx + c = 0 are real and equal. Then
1)b² - 4ac < 0
2)b² - 4ac = 0
3)b² - 4ac >0
4)None of these​

Answer 1

$\huge\underline{\mathfrak{Question:}}$

If the roots of ax2 +bx+c= 0 are real and unequal, then b2-4ac <0. Is it true?

ANSWER:

If the roots of quadratic equation are real and equal then discriminant is greater than 0 so the given statement is false.

Additional information:

When;

$\bold{b^2-4ac}$<0

then it has unequal roots.

and

$\bold{b^2-4ac=0,}$

then it has equal and real roots.

Answer 2

Answer:

Step-by-step explanation:

option 2 b^2-4ac=0 is the correct answer.

When a, b and c are real numbers, a ≠ 0 and discriminant is zero (i.e., b2 - 4ac = 0), then the roots α and β of the quadratic equation ax2 + bx + c = 0 are real and equal.