Question

the roots of each of the following quadratic equation are real and equal find k

Kx*(x-2)+6=0

Answer 1

you get the answer from the above picture

Answer 2

The value of k will be "6".

Step-by-step explanation:

$The \ given \ equation \ is:\\kx(x-2)+6=0\\kx^2-2kx+6=0\\So,\\a=k\\b=-2k\\c=6\\If \ it \ has \ real \ and \ equal \ roots,then\\b^2-4ac=0\\On \ putting \ the \ values \ in \ the \ above \ equation,we \ get\\(-2k)^2-4(k)(6)=0\\4k^2-24k=0\\4k(k-6)=0\\k-6=0\\k=6$

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