Question

The roots of equation 3^x+2 + 3^-x= 10 are

Answer 1

Answer:

$3^{x}$ + 2 + $3^{-x}$ = 10

$3^{x}$ + $3^{-x}$ = 10 - 2

$3^{x}$ +1 /

($3^{x}$ X

(3 X 3 $)^{x}$ + 1 = 8 X  $3^{x}$

(9 $)^{x}$ + 1 = 8. $3^{x}$

(9 $)^{x}$ -8. $3^{x}$ + 1 = 0

yet to solve.....