Math, asked by aa4249592, 8 months ago

the roots of equation 4x^2-2x(a^2+b^2)+(ab)^2=0​

Answers

Answered by shristipal
0

Answer:

Given,

4x

2

−2(a

2

+b

2

)x+a

2

b

2

=0

For general Quadratic Equation,

ax

2

+bx+c=0

a=4,b=−2(a

2

+b

2

),c=a

2

b

2

According to formulae,

x=

2a

−b+

b

2

−4ac

=

2

a

2

x=

2a

−b−

b

2

−4ac

=

2

b

2

Answered by rajsharma4645
3

Answer:

4x^2-2x(a^2+b^2)+(ab)^2=0

(2x)^2-2x(a+b)(a-b)+(ab)^2=0...

x=a-b/2

x=a+b/2

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