Question

The roots of equation is x^2+2√3x+3=0,are​

Answer 1

Answer:

x²+2√3 x + 3 = 0

=> x² + √3x + √3x +3 = 0

=> x(x+√3) + √3 (x+√3) = 0

=>( x+√3)(x+√3) = 0

=> x= -√3 , x= -√3

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Answer 2

Answer:

$x = - \sqrt{3}$

Step-by-step explanation:

${x}^{2} + 2 \sqrt{3} x + 3 = 0$

${x}^{2} + \sqrt{3} x + \sqrt{3} x + 3 = 0$

$x(x + \sqrt{3} ) + \sqrt{3} (x + \sqrt{3} ) = 0$

$(x + \sqrt{3} )(x + \sqrt{3} ) = 0$

${(x + \sqrt{3} )}^{2} = 0$

$x = - \sqrt{3}$

Hope it helps