Question

The roots of equation X+16/x=10 are ?

Answer 1

Answer:

I hope this will help you

pls follow me!!!!!

Answer 2

Answer:

The answer is

$x=8\\x=2$

step-by-step explanation:

It was found that the equations we want to solve can be changed into comparable equations with one side equal to zero. We can therefore solve other scenarios if we can solve that one! discover only one technique to handle them all. The roots of a quadratic formula are the values of the factors that fulfil the equation. In other words, if f(α) = 0, then x = α is a root of the quadratic equation f(x). The x-coordinates of the sites where the curve y = f(x) intersects the x-axis are the real roots of an equation f(x) = 0.

$x+\frac{16}{x} =10$

$\frac{xx}{x} +\frac{16}{x} =10$

$xx+\frac{16}{x} =10$

$x^{2} +\frac{16}{x} =10$

$x.x^{2} +\frac{16}{x} =x.10$

$x^{2} +16=x.10$

$x^{2} +16=10x$

$x^{2} +16-10x=0$

$x^{2} -10x+16=0$

$x=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}$

Once the equation is in simple form, take the variables a, b, and c and enter them into the quadratic equation.

$x^{2} -10x+16=0$

$a = 1\\b = -10\\c = 16$

$x=\frac{-(-10)+-\sqrt{(-10)^{2}-4.1.16 } }{2.1}$

$x=10+-\frac{6}{2}$

$x=10+\frac{6}{2}$

$x=10-\frac{6}{2}$

$x=8\\x=2$

#SPJ3