the roots of equation x^3 + 7x^2 - 21x -27 = 0
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Answered by
8
Here is ur answer........
Firstly by Hit and trail method
try to find one root of the equation that is -1
if we put x=-1
then the answer will come out 0 and it is verified that this the root of this equation
now divide the given equation with x+1=0
that is x^3+7x^2-21x-27/(x+1)
the quotient comes out to be
x^2+6x-1=0
so now find roots of this equation
by solving this equation x comes out to be 0.45 and 6.45
so all roots are
(x+1)(x-0.45)(x-6.45)
hope it helps uh
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Firstly by Hit and trail method
try to find one root of the equation that is -1
if we put x=-1
then the answer will come out 0 and it is verified that this the root of this equation
now divide the given equation with x+1=0
that is x^3+7x^2-21x-27/(x+1)
the quotient comes out to be
x^2+6x-1=0
so now find roots of this equation
by solving this equation x comes out to be 0.45 and 6.45
so all roots are
(x+1)(x-0.45)(x-6.45)
hope it helps uh
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Anonymous:
Superb topper
thanks topper
Answered by
6
Answer:
x = 3,-1,-9
Step-by-step explanation:
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