Question

The roots of given quadratic equation are​

Answer 1

ANSWER:

• Roots of the given quadrtic polynomial is -√3 or -7√3/3

GIVEN:

• P(x) = √3x²+10x+7√3 = 0

TO FIND:

• Roots of the above expression.

SOLUTION:

=> √3x²+10x+7√3 = 0

=> √3x²+3x+7x+7√3 = 0

=> (√3x²+3x)+(7x+7√3) = 0

=> √3x(x+√3) +7(x+√3) = 0

=> (x+√3)(√3x+7) = 0

Either (x+√3) = 0

=> x = -√3

Either (√3x+7) = 0

=> √3x = -7

=> x = -7/√3

After rationalising

=> x = -7√3/3

Roots of the given quadrtic polynomial is -√3 or -7√3/3

NOTE:

Some important formulas:

(a+b)² = a²+b²+2ab

(a-b)² = a²+b²-2ab

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²+b²-ab)

a³-b³ = (a-b)(a²+b²+ab)

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab