Question

The roots of kx^2 - 2kx +6 =0 are real and equal then find k

Answer 1

Answer:

Value of k=6

Step-by-step explanation:

Given Quadratic equation:

kx²-2kx+6=0 has equal roots.

Compare above equation with

ax²+bx+c=0 we get

a = k , b = -2k , c = 6

Now ,

Discreminant (D)=0

/* given roots are equal */

b²-4ac=0

=> (-2k)²-4×(k)×6 = 0

=> 4k²-24k=0

=> 4k(k-6)=0

=> 4k=0 Or k-6=0

=> k=0 Or k=6

Here , k = 0 is not possible.

Therefore,.

Value of k=6