the roots of qe x2 +7x+12=0 are
with explanation
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Answer:
x² + 7x + 12 = 0
x² + 3x + 4x + 12 = 0
x(x + 3) + 4(x + 3) = 0
(x + 3) (x + 4) = 0
x = - 3 (or) x = - 4.
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