Math, asked by sadafnimra, 7 hours ago

the roots of qe x2 +7x+12=0 are

with explanation ​

Answers

Answered by ramg777
0

Answer:

x² + 7x + 12 = 0

x² + 3x + 4x + 12 = 0

x(x + 3) + 4(x + 3) = 0

(x + 3) (x + 4) = 0

x = - 3 (or) x = - 4.

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