Question

the roots of quadratic equation 3(x+3) square =48 are?

Answer 1

Answer:

1,-7

Step-by-step explanation:

$3(x+3)^{2}=48\\(x+3)^{2} = 16\\(x+3) = +4 , -4\\x = 1,-7$

Therefore the roots of the given quadratic equation are : 1,-7