Question

the roots of quadratic equation -39 X square + 8 x + 1 is equal to zero​

Answer 1

Answer:

p(x)=–39x²+8x+1=0

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a}$

Using the Quadratic Formula:

$x = \frac{ - 8± \sqrt{ {8}^{2} - 4( - 39)(1) } }{(2)( - 39)}$

$x = \frac{ - 8± \sqrt{64 + 156} }{ - 78}$

$x = \frac{ - 8± \sqrt{220} }{ - 78}$

$x = \frac{ - 8± \sqrt{2 {}^{2} \times 5 \times 11 } }{ - 78}$

$x = \frac{ - 8± 2\sqrt{55} }{ - 78} = \frac{ - 4± \sqrt{55} }{ - 39}$

Therefore,

$x = \frac{ 4 - \sqrt{55} }{39}$

OR

$x = \frac{ 4 + \sqrt{55} }{ 39}$