The roots of quadratic equation 3m²+4m+k=0 are real then find value of k?
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Answer:
k<4/3 or k=4/3
Step-by-step explanation:
3m²+4m+k=0
where a=3, b=4 &c=k
As the roots of the given equation are equal then
D=0 or D>0
b²-4ac=0 or b²-4ac>0
4²-4×3k =0 or 4²-4×3k>0
4(4-3k)=0 or 4(4-3k)>0
4=3k or 4>3k
therefore, either k=4/3 or k<4/3
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