Question

the roots of quadratic equation(3x-2) (2x+1) are​

Answer 1

Answer:

6x^2+3x-4x-2

6x^2-x-2

so

6x^2 -4x+3x-2

2x (3x-2) +1 (3x-2)

(2x+1)(3x-2)

(2x+1)=0

x= --1/2

or

x=2/3