The roots of quadratic equation 3y2+ky + 12= 0,are real and equal. Complete Avticty to find value of k
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Answer:
Step-by-step explanation:
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It is given that roots of p(x) are real and equal
So:
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⇒k=12.
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Answered by
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Answer:
a) 12
Step-by-step explanation:
3y² + ky + 12 = 0
if it has equal roots, then the determinant = 0
determinant of a quadratic equation = √(b² - 4ac) = 0
a = 3 , b = k , c = 12
√(b² - 4ac) = 0
√(k² - 4 × 3 × 12) = 0
√(k² - 144) = 0 {square both sides}
k² - 144 = 0
k² = 144
k = 12
⇒ a) 12
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