Question

The roots of quadratic equation
4x²_16=0 are
A)±1
B) ± 2
c) ±4
d)± 8
please frnds it's urgent​

Answer 1

answer:4x^2-16=0

4x^2=16

x^2=4

X=± 2

hope this helps you

Answer 2

Step-by-step explanation:

4x^2-16=4(x^2 - 4)

= 4[(x+2)(x-2)]

So if we substitute x=2

Then ,

4[(4)(0)]=0

0=0