Question

the roots of quadratic equation 5 x square - 4 x + 50 is equal to zero​

Answer 1

Answer:

$5 {x}^{2} - 4x + 50 = 0$

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a}$

$x = \frac{4 + \sqrt{ - 984} }{10}$

OR

$x = \frac{4 - \sqrt{ - 984} }{10}$