Question

 The roots of quadratic equation 5xᒾ -4x +5=0 are​

Answer 1

Answer:

sory

Step-by-step explanation:

Answer 2

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\bigstar\boxed{\bf\red{Question}}$

$\: \: \: \: \clubsuit \bf{ \: the \: roots \: of \: quadratic \: equation \: 5 {x}^{2} - 4x + 5 = 0 \: are}$

$\underline{\underline{{\purple{\sf Given\: Equation:}}}}$

$\: \: \: \: \: \to \bf{5 {x}^{2} - 4x + 5 = 0}$

$\: \: \: \: \huge \boxed{ \sf{ \: by \: discriminant \: form}}$

$\: \: \: \: \implies \tt{ {b}^{2} - 4ac}$

$\: \: \: \to \tt { {b}^{2} - 4ac}$

$\: \: \: \spadesuit \bf{ \: here \: b = - 4 \: and \: a = 5 \: and \: c = 5}$

$\: \: \: \: \: \to { {( - 4)}^{2} - 4(5)(5)}$

$\: \: \: \to \tt {16 - 100 < 0}$

$\: \: \: \: \to \tt{ - 84 < 0}$

$\: \: \: \: \: \star \sf{ \ \: by \: formula \: method}$

$\: \: \: \implies \bf { \: x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }$

$\: \: \: \: \: \implies \bf{x = \frac{ 4 \pm \sqrt{ - 84} }{10} }$

$\: \: \: \: \implies \bf{x = \frac{4 \pm 2\sqrt{21} }{10} }$

$\: \: \: \implies \bf{x = \frac{2(2 \pm \sqrt{21}) }{2 \times 5} }$

$\: \: \: \: \implies \bf{x = \cancel\frac{2}{5} \times \frac{2 \pm \sqrt{21} }{5} }$

$\: \: \: \: \implies \bf{x = \frac{2 \pm \sqrt{21} }{5} }$

$\: \: \: \: \: \blue \bigstar \displaystyle \sf{here \: we \: get \: two \: roots \: because \: of \: degree \: 2 \: }$

$\: \: \: \pink \bigstar \displaystyle \sf{our \: answer \: will \: be \: x = \frac{2 + \sqrt{21} }{5} \: and \: x = \frac{2 - \sqrt{21} }{5} }$

$\: \: \: \clubsuit\boxed{ \bf{hence \:proved}}$