Question

the roots of quadratic equation 5xᒾ -4x +5=0 are which equation​

Answer 1

Step-by-step explanation:

5x²- 4x +5=0

compare equation with ax2+bx+c=0

a=5;b=-4;c=5

b²-4ac=(-4)²-4×5×5

=16-100

= -84

b²-4ac<0.

therefore, roots of equation is not real.

Answer 2

a= 5

b== -4

c=5

now b^2-4 ac = -4^2-4(5)(5)=16- 100=. -84

now applying formula

x=( - b±√b^2-4 ac)/2 a

x= {-(-4)±(-84)}/2(5)

x={4±(-84)}/10

however, the square of a number cannot be negative

so, therefore, ther Eid no real root for the given equations