Question

The roots of quadratic equation x2_3x+7=0are

​

Answer 1

Answer:

x2-3x+7=0

x = (3 +- √(9-28))/2

x = (3 +- √(-19) )/2

So,

x1 = (3 + √(-19) )/2

x1 = (3 + i*4.36 )/2

x2 = (3 - √(-19) )/2

x2 = (3 - i*4.36 )/2