Question

the roots of quadratic equations 5x^2-4x+5=0​

Answer 1

Answer:

Step-by-step explanation:

$5x^2-4x +5=0$

use quadratic formula$\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

here a=5, b= -4 and c=5

now solving this

x=$\frac{-5 \pm \sqrt{16-4(5)(5)}}{2(5)}$

x=$\frac{-5\pm\sqrt{-84}}{10}$

x=$\frac{-5 \pm 2 i\sqrt{21}}{10}$

it has complex roots