Question

The roots Of quadric equation 6x²-x-2=0 are

Answer 1

Answer:

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Answer 2

$6 {x}^{2} - x - 2 = 0$

$6 {x}^{2} + 3x - 4x - 2 = 0$

$3x(2x + 1) - 2(2x + 1) = 0$

or

$(2x + 1)(3x - 2) = 0$

Either

$2x + 1 = 0$

$x = \frac{ - 1}{2}$

Or

$3x - 2 = 0$

$x = \frac{2}{3}$

x = -1/2, 2/3