Question

The roots of
$x ^{2}$
+ kr + k = 0 are real and equal, find k.
(A)0 (B)4 (C) 0 or 4 (D) 2 naponta​

Answer 1

Answer:

HERE'S YOUR ANSWER

If the polynomial has real and equal root....

D= 0

$d = {b}^{2} - 4ac \\ \\ d = {k}^{2} - 4k$

D= 0

${k}^{2} - 4k = 0 \\ \\ k(k - 4) = 0 \\ \\ k = 4$

So the answer is (B) 4

Hope it helps ✌...