Question

the roots of the eqation x^2+5x+1=0 are​

Answer 1

Solution :-

By using quadratic formula :-

$\implies\boxed{\sf x = \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }$

Here

• a = 1
• b = 5
• c = 1

Substitute values in formula

$\sf x = \dfrac{ - 5 \pm \sqrt{ {5}^{2} - 4 \times 1 \times 1 } }{2 \times 1}$

$\sf x = \dfrac{ - 5 \pm \sqrt{21} }{2 }$

Taking +ve sign

$\sf x = \dfrac{ - 5 + \sqrt{21} }{2 }$

Taking - ve sign

$\sf x = \dfrac{ - 5 - \sqrt{21} }{2 }$

Answer 2

Answer:

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