the roots of the equation 1/x - 1/x-2 =3 are A) 3+√5/2 B) 3+√3/3 C)3+√5/3 D)3+√3/2
Answers
Answered by
0
Answer:
The question is wrong.
Here 1/x cancels each other
Answered by
1
Answer:
1/x - 1/(x-2)=3
=> x-2-x/x(x-2) = 3
=> -2/x²-2x =3
=> -2 = 3x²-6x
=> 3x²-6x +2 = 0
now,
x= -b±√(b²-4ac)/ 2a
= 6±√(36-24)/ 6
= (6±√ 12)/6
=( 6±2√3)/6
= 2( 3±√3)/6
= 3±√3/3
hence the correct answer is option b.
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