Question

The roots of the equation 2+−(+1)=0, where is a constant, are

Answer 1

equation is wrong I think so,
2+-(+1)=0
2+ -1=0
2-1=0
1=0
1 is constant term ,is this helpful to you? if yes then fine ,if not then tell me .

Answer 2

X^2 - 3x - m(m+3) = 0

=> x^2 + mx - (m+3)x- m(m+3) = 0

=> x(x+m) - (m+3)(x+m) = 0

=> (x+m) (x-m-3) = 0

x = - m and m+3

(question might be mingled )
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